Transpose Matrices Using zip(*) in Python

Question

Given a 2D matrix (list of lists), transpose rows into columns using a single pythonic statement with `zip()`.

Accepted Answer

Optimal Solution:
def transpose_matrix(matrix: list[list[int]]) -> list[list[int]]:
    # Unpacks rows as separate positional arguments to zip
    return [list(col) for col in zip(*matrix)]

Technical Explanation:
`zip(*matrix)` unpacks the rows so that `zip()` pairs the 1st elements of each row together, then the 2nd elements, transposing rows to columns.